2015 AMC 10B 第 18 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

18.

Johann 有 6464 枚公平硬币。他抛所有硬币。任何反面朝上的硬币都再抛一次。第二次仍为反面的硬币再抛第三次。现在正面朝上的硬币的期望数量是多少?

Johann has 6464 fair coins. He flips all the coins. Any coin that lands on tails is tossed again. Coins that land on tails on the second toss are tossed a third time. What is the expected number of coins that are now heads?

3232

4040

4848

5656

6464

答案:D
知识点:期望值对立事件概率
难度评级:1070
解答:

一枚硬币最后仍为反面,当且仅当它连续 33 次都是反面,概率为 18\frac 18。因此任意一枚硬币最后为正面的概率为 78\frac 78

由于一枚硬币为正面的概率是 78\frac78,且一共有 6464 枚硬币,所以现在正面朝上的硬币期望数为 6478=56.64 \cdot \dfrac 78 = 56.

所以正确答案是 D

A coin ends as tails if and only if it has 33 flips that are tails, which happens with probability 18.\frac 18. Thus, the probability of any coin being heads is 78.\frac 78 .

Since each of the 6464 coins ends as heads with probability 78,\frac78, linearity of expectation gives the expected number of coins that are now heads: 6478=56.64 \cdot \dfrac 78 = 56.

Thus, the correct answer is D .

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