2013 AMC 10A 第 5 题

先试着解答 2013 AMC 10A 第 5 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2013 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

5.

Tom、Dorothy 和 Sammy 一起度假,并同意平均分摊费用。旅途中 Tom 支付了 $105\$105,Dorothy 支付了 $125\$125,Sammy 支付了 $175\$175。为了平均分摊,Tom 给 Sammy tt 美元,Dorothy 给 Sammy dd 美元。t−dt-d 是多少?
Tom, Dorothy, and Sammy went on a vacation and agreed to split the costs evenly. During their trip Tom paid $105,\$105, Dorothy paid $125,\$125, and Sammy paid $175.\$175. In order to share costs equally, Tom gave Sammy tt dollars, and Dorothy gave Sammy dd dollars. What is t−d?t-d?
1515
2020
2525
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3535
答案:B
知识点:平均数钱币
小提示:
先求总费用和每个人应承担的份额。
First find the total trip cost and each person’s fair share
大提示:
Tom 和 Dorothy 各把低于应付份额的差额给 Sammy。
Tom and Dorothy each pay Sammy the amount they are short of a fair share
解答:
总费用为 $105+$125+$175=$405\$105+\$125+\$175=\$405,所以每人应承担 $405÷3=$135\$405\div3=\$135。
Tom 少付 $30\$30,Dorothy 少付 $10\$10,因此 t=30t=30 且 d=10d=10。
所以 t−d=30−10=20t-d=30-10=20。
所以正确答案是 B。
The total cost was $105+$125+$175=$405\$105+\$125+\$175=\$405, so each person’s share was $405÷3=$135\$405\div3=\$135.
Tom paid $30\$30 less than his share, and Dorothy paid $10\$10 less than her share, so t=30t=30 and d=10d=10.
Therefore t−d=30−10=20t-d=30-10=20.
Thus, B is the correct answer.
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