2012 AMC 10A 第 18 题

先试着解答 2012 AMC 10A 第 18 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2012 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

18.

图中的闭合曲线由 99 段全等圆弧组成,每段圆弧长为 2π3\dfrac{2\pi}{3},每段对应圆的圆心都是边长为 22 的正六边形的某个顶点。该闭合曲线围成的面积是多少?
The closed curve in the figure is made up of 99 congruent circular arcs each of length 2π3,\dfrac{2\pi}{3}, where each of the centers of the corresponding circles is among the vertices of a regular hexagon of side 2.2. What is the area enclosed by the curve?
2π+62\pi+6
2π+432\pi+4\sqrt{3}
3π+43\pi+4
2π+33+22\pi+3\sqrt{3}+2
π+63\pi+6\sqrt{3}
答案:E
知识点:扇形正多边形面积分割
小提示:
每段圆弧都是单位圆上的 120∘120^\circ 弧。
Each arc is a 120∘120^\circ arc of a unit circle
大提示:
把这些扇形块围绕正六边形重新拼接。
Rearrange the sector pieces around the regular hexagon
解答:
每段圆弧的半径都是 11,长度都是 2π3\frac{2\pi}{3},所以对应的各个扇形面积都相同。如图所示,这些扇形块可以重新拼接:添加到正六边形上的部分合起来恰好构成一个单位圆。
正六边形由六个边长为 22 的等边三角形拼成,所以它的面积为 6(34⋅22)=63。6\left(\dfrac{\sqrt3}{4}\cdot2^2\right)=6\sqrt3\text{。} 再加上那个单位圆,围成的总面积为 π+63\pi+6\sqrt3。
所以正确答案是 E。
Each arc has radius 11 and length 2π3,\frac{2\pi}{3}, so the corresponding circular sectors all have the same area. As the diagram shows, the sector pieces may be rearranged: everything added to the regular hexagon combines to exactly one unit circle.
The regular hexagon is made of six equilateral triangles of side 2,2, so its area is 6(34⋅22)=63.6\left(\dfrac{\sqrt3}{4}\cdot2^2\right)=6\sqrt3. Adding the unit circle gives a total enclosed area of π+63.\pi+6\sqrt3.
Thus, E is the correct answer.
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