2011 AMC 10B 第 2 题

先试着解答 2011 AMC 10B 第 2 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2011 AMC 10B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

Josanna 到目前为止的考试分数为 9090、8080、7070、6060 和 8585。她的目标是在下一次考试后把考试平均分至少提高 33 分。她至少需要在下一次考试中得到多少分?
Josanna’s test scores to date are 90,90, 80,80, 70,70, 60,60, and 85.85. Her goal is to raise her test average at least 33 points with her next test. What is the minimum test score she would need to accomplish this goal?
8080
8282
8585
9090
9595
答案:E
知识点:平均数逆推法
小提示:
求当前总分和目标平均分。
Find the current total score and target average
大提示:
第六次考试后总分必须达到 6⋅806\cdot80。
The sixth score must bring the total to 6⋅806\cdot80
解答:
她当前的平均分为 90+80+70+60+855=77,\dfrac{90+80+70+60+85}5 = 77\text{,}而总分为 385385。目标平均分为 8080,所以六次考试所需的总分为 80⋅680\cdot 6。因此下一次考试至少需要得 80⋅6−385=95。80\cdot 6-385 = 95\text{。}
所以正确答案是 E。
Her current average is 90+80+70+60+855=77,\dfrac{90+80+70+60+85}5 = 77, and the sum of her scores is 385.385. The desired average is then 80,80, so the sum of scores required is 80⋅6.80\cdot 6. Therefore, the answer is 80⋅6−385=95.80\cdot 6-385 = 95.
Thus, the correct answer is E .
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