2011 AMC 10B 第 2 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

Josanna 到目前为止的考试分数为 90,80,70,6090, 80, 70, 608585。她的目标是在下一次考试后把考试平均分至少提高 33 分。她至少需要在下一次考试中得到多少分?

Josanna's test scores to date are 90,80,70,60,90, 80, 70, 60, and 85.85. Her goal is to raise her test average at least 33 points with her next test. What is the minimum test score she would need to accomplish this goal?

8080

8282

8585

9090

9595

答案:E
知识点:平均数逆推法
难度评级:870
解答:

她当前的平均分为 而总分为 385385。目标平均分为 8080,所以六次考试所需的总分为 80680\cdot 6。因此下一次考试至少需要得 90+80+70+60+855=77,\dfrac{90+80+70+60+85}5 = 77, 806385=95.80\cdot 6-385 = 95.

所以正确答案是 E

Her current average is 90+80+70+60+855=77,\dfrac{90+80+70+60+85}5 = 77, and the sum of her scores is 385.385. The desired average is then 80,80, so the sum of scores required is 806.80\cdot 6. Therefore, the answer is 806385=95.80\cdot 6-385 = 95.

Thus, the correct answer is E .

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