2023 AMC 10A Problem 2

Below is the professionally curated solution for Problem 2 of the 2023 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10A solutions, or check the answer key.

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Concepts:linear equationfraction

Difficulty rating: 1080

2.

The weight of 13\frac{1}{3} of a large pizza together with 3123\frac{1}{2} cups of orange slices is the same as the weight of 34\frac{3}{4} of a large pizza together with 12\frac{1}{2} cup of orange slices. A cup of orange slices weighs 14\frac{1}{4} of a pound. What is the weight, in pounds, of a large pizza?

1451\frac{4}{5}

22

2252\frac{2}{5}

33

3353\frac{3}{5}

Solution:

Let pp be the pizza's weight. A cup of orange slices is 14\frac14 pound, so the two sides balance as 13p+7214=34p+1214,\frac13 p + \frac72 \cdot \frac14 = \frac34 p + \frac12 \cdot \frac14, that is 13p+78=34p+18.\frac13 p + \frac78 = \frac34 p + \frac18. Collect the pizza terms: 68=(3413)p=512p.\frac68 = \left(\frac34 - \frac13\right)p = \frac{5}{12}p. So p=34125=95=145.p = \frac34 \cdot \frac{12}{5} = \frac95 = 1\frac45. Therefore, the answer is A.

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