2018 AMC 10B Problem 2

Below is the professionally curated solution for Problem 2 of the 2018 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10B solutions, or check the answer key.

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Concepts:distance rate and time

Difficulty rating: 980

2.

Sam drove 9696 miles in 9090 minutes. His average speed during the first 3030 minutes was 6060 mph (miles per hour), and his average speed during the second 3030 minutes was 6565 mph. What was his average speed, in mph, during the last 3030 minutes?

6464

6565

6666

6767

6868

Solution:

Each leg is half an hour. In the first, Sam drove 6012=3060 \cdot \tfrac12 = 30 miles; in the second, 6512=32.565 \cdot \tfrac12 = 32.5 miles. That's 62.562.5 miles so far. That leaves 9662.5=33.596 - 62.5 = 33.5 miles for the last half hour, which is a speed of 33.5/12=6733.5 / \tfrac12 = 67 mph. Therefore, the answer is D.

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