2010 AMC 10B 第 3 题

先试着解答 2010 AMC 10B 第 3 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2010 AMC 10B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

一个抽屉里有红、绿、蓝、白四种颜色的袜子,每种颜色至少 22 只。至少要从抽屉里取出多少只袜子,才能保证有一双同色袜子?
A drawer contains red, green, blue, and white socks with at least 22 of each color. What is the minimum number of socks that must be pulled from the drawer to guarantee a matching pair?
33
44
55
88
99
答案:C
知识点:抽屉原理
小提示:
考虑出现一双袜子之前的最坏情况。
Use the worst case before a pair appears
大提示:
你可能先各取出四种颜色的一只袜子。
You can draw one sock of each of the four colors first
解答:
为了尽量延迟出现同色一双,最多可以先取出每种颜色各一只袜子。
一共有 44 种颜色,因此取出四只时仍可能没有同色一双。
再取一只就必然与其中一种颜色配成一双,所以需要 4+1=54 + 1 = 5 只。
所以正确答案是 C。
To maximize the number of socks, we want to grab as many single socks as possible before getting a pair.
There are 44 colors, which means that we can draw one sock of each color before drawing a pair.
This means that it takes at least 4+1=54 + 1 = 5 socks to be drawn before a pair is guaranteed.
Thus, C is the correct answer.
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