2004 AMC 10A 第 13 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

在一次聚会上,每位男士正好与三位女士跳舞,每位女士正好与两位男士跳舞。共有十二位男士参加聚会。共有多少位女士参加?

At a party, each man danced with exactly three women and each woman danced with exactly two men. Twelve men attended the party. How many women attended the party?

88

1212

1616

1818

2424

答案:D
知识点:双重计数数对计数
难度评级:1190
解答:

从男士角度数,跳舞配对数为 123=3612 \cdot 3 = 36。每位女士恰好在 22 对中,所以女士人数为 362=18. \dfrac{36}{2} = 18.

所以正确答案是 D

The number of dancing pairs is 123=36,12 \cdot 3 = 36, counting from the men's side. Each woman was in exactly 22 pairs, so the number of women is 362=18. \dfrac{36}{2} = 18.

Thus, the correct answer is D.

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