2002 AMC 10B 第 8 题

先试着解答 2002 AMC 10B 第 8 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2002 AMC 10B 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

假设 NN 年的七月有五个星期一。下列哪一天一定会在 NN 年八月出现五次?(注意:两个月都有 3131 天。)

Suppose July of year NN has five Mondays. Which of the following must occur five times in August of year N?N? (Note: both months have 3131 days.)

星期一

Monday

星期二

Tuesday

星期三

Wednesday

星期四

Thursday

星期五

Friday

答案:D
知识点:日期与时间模运算分类讨论
难度评级:1240
解答:

3131 天等于 44 周又 33 天,所以恰好是每月第 11、第 22、第 33 日所对应的三个星期几会出现五次。

七月要有五个星期一,星期一就必须是七月第 11、第 22 或第 33 日。三种情况下,八月 11 日分别是星期三、星期四或星期五,而八月出现五次的三个星期几都包括星期四。

也可以直接看出:七月有 3131 天,所以八月 11 日与七月 44 日是同一星期几。无论星期一是七月第 11、第 22 还是第 33 日,八月出现五次的三个星期几中总有星期四。

所以正确答案是 D

A 3131-day month is 44 weeks plus 33 extra days, so exactly the weekdays of the 11st, 22nd, and 33rd of the month occur five times.

For July to have five Mondays, Monday must be one of July 1,1, 2,2, or 3.3. In all three cases August 11 lands on a Wednesday, Thursday, or Friday, and the common weekday among the resulting five-time days is Thursday.

More directly, since July has 3131 days, August 11 is the same weekday as July 4.4. With Monday on July 1,1, 2,2, or 3,3, the three five-time weekdays of August always include Thursday.

Thus, the correct answer is D.

← 第 7 题#7
完整试卷

其他年份的第 8 题