2016 AMC 8 Problem 24

Below is the video solution and professionally curated solution for Problem 24 of the 2016 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

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Concepts:divisibilitycasework

Difficulty rating: 1580

24.

The digits 1,1, 2,2, 3,3, 4,4, and 55 are each used once to write a five-digit number PQRST.PQRST. The three-digit number PQRPQR is divisible by 4,4, the three-digit number QRSQRS is divisible by 5,5, and the three-digit number RSTRST is divisible by 3.3. What is P?P?

1 1

2 2

3 3

4 4

5 5

Video solution:
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Written solution:

Since QRSQRS is divisible by 5,5, we know that S=5.S = 5.

Since PQRPQR is divisible by 4,4, QRQR equals either 12,24,12, 24, or 32.32.

If QR=12,QR=12, then R=2,R=2, so RST=25TRST=25T cannot be divisible by 33 using the remaining digits. If QR=32,QR=32, then R=2R=2 again, giving the same obstacle. Thus QR=24,QR=24, and then RST=45T.RST=45T. Among the remaining digits, only T=3T=3 makes 453453 divisible by 33.

Therefore, PQRST=12453.PQRST = 12453.

Thus, A is the correct answer.

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