2025 AMC 10B 第 8 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

Emmy 对 Max 说:“我今天订了 3636 件数学俱乐部运动衫。”Max 问:“每件多少钱?”Emmy 回答:“我给你一个提示。总价是 $ABB.BA\$\underline{A}\,\underline{B}\,\underline{B}.\underline{B}\,\underline{A},其中 AABB 是数字,且 A0A \ne 0。”停顿片刻后,Max 说:“这个价格不错。”求 A+BA + B

Emmy says to Max, "I ordered 3636 math club sweatshirts today." Max asks, "How much did each shirt cost?" Emmy responds, "I'll give you a hint. The total cost was $ABB.BA,\$\underline{A}\,\underline{B}\,\underline{B}.\underline{B}\,\underline{A}, where AA and BB are digits and A0.A \ne 0." After a pause, Max says, "That was a good price." What is A+B?A + B?

77

88

1111

1414

1515

答案:C
知识点:整除性模运算位值
难度评级:1350
解答:

以美分为单位,总价是 10000A+1000B+100B10000A + 1000B + 100B +10B+A+ 10B + A =10001A+1110B= 10001A + 1110B。它要平均分给 3636 件运动衫,所以能被 3636 整除。因为 100012910001 \equiv 29111030(mod36)1110 \equiv 30 \pmod{36},所以需要 29A+30B029A + 30B \equiv 0,也就是 7A+6B0(mod36)7A + 6B \equiv 0 \pmod{36}。在 A0A \ne 0 的数字解中,唯一可行的是 A=6,B=5A = 6, B = 5,因为 76+65=727 \cdot 6 + 6 \cdot 5 = 72。这对应 $655.56\$655.56,也就是每件 $18.21\$18.21,所以 A+B=11A + B = 11。因此正确答案是 C

In cents the total is 10000A+1000B+100B10000A + 1000B + 100B +10B+A+ 10B + A =10001A+1110B.= 10001A + 1110B. Split evenly among 3636 shirts, so it's divisible by 36.36. Now 100012910001 \equiv 29 and 111030(mod36),1110 \equiv 30 \pmod{36}, so we need 29A+30B0,29A + 30B \equiv 0, which reduces to 7A+6B0(mod36).7A + 6B \equiv 0 \pmod{36}. The only digit solution with A0A \ne 0 is A=6,B=5,A = 6, B = 5, since 76+65=72.7 \cdot 6 + 6 \cdot 5 = 72. That's $655.56,\$655.56, or $18.21\$18.21 a shirt, so A+B=11.A + B = 11. Therefore, the answer is C.

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