2012 AMC 10A 第 8 题

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8.

三个非负整数两两相加得到的和分别为 12,1712, 171919。这三个数中的中间那个数是多少?

The sums of three whole numbers taken in pairs are 12,17,12, 17, and 19.19. What is the middle number?

44

55

66

77

88

答案:D
知识点:方程组
难度评级:1020
解答:

设三个数为 a,b,ca, b, c,且 a<b<ca \lt b \lt c。由于三个和都不同,所以这三个数也互不相等。

题意给出 以及 a+b=12,a+c=17, a + b = 12, a + c = 17, b+c=19. b + c = 19.

把三式相加,得到 2(a+b+c)=48. 2(a + b + c) = 48.

因此 再减去 得到 b=7b = 7a+b+c=24, a + b + c = 24, a+c=17, a + c = 17,

所以正确答案是 D

Let the three numbers be a,b,ca, b, c where a<b<c.a \lt b \lt c. None of them are equal, since all three sums are different.

Then a+b=12,a+c=17, a + b = 12, a + c = 17, and b+c=19. b + c = 19.

Adding all three equations together gives us 2(a+b+c)=48. 2(a + b + c) = 48.

Then a+b+c=24, a + b + c = 24, from which we can subtract a+c=17, a + c = 17, to get b=7.b = 7.

Thus, D is the correct answer.

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