2009 AMC 10B 第 14 题

先试着解答 2009 AMC 10B 第 14 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2009 AMC 10B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

14.

星期一,Millie 往喂鸟器中放入一夸脱种子,其中 25%25\% 是小米。之后每天她都会再加入一夸脱同样配比的种子,不取出剩下的种子。每天鸟只吃掉喂鸟器中小米的 25%25\%,但会吃掉所有其他种子。在哪一天,Millie 刚放入种子后,鸟会发现喂鸟器中超过一半的种子是小米?
On Monday, Millie puts a quart of seeds, 25%25\% of which are millet, into a bird feeder. On each successive day she adds another quart of the same mix of seeds without removing any seeds that are left. Each day the birds eat only 25%25\% of the millet in the feeder, but they eat all of the other seeds. On which day, just after Millie has placed the seeds, will the birds find that more than half the seeds in the feeder are millet?
星期二
Tuesday
星期三
Wednesday
星期四
Thursday
星期五
Friday
星期六
Saturday
答案:D
知识点:等比数列递推不等式
小提示:
每天留下的小米乘以 34\dfrac34,再加入 14\dfrac14 夸脱。
Each day the standing millet is multiplied by 34,\dfrac34, then 14\dfrac14 quart is added
大提示:
其他种子总是 34\dfrac34 夸脱;求小米何时首次超过它。
Other seeds always total 34\dfrac34 quart; find when millet first exceeds that
解答:
每夸脱新种子加入 14\dfrac14 夸脱小米,鸟会留下已有小米的 34\dfrac34。第 nn 天加入后的小米量为 14(1+34+⋯+(34)n−1)=1−(34)n。 \begin{gathered} \dfrac14\left(1+\dfrac34+\cdots+\Big(\dfrac34\Big)^{n-1}\right) \\ = 1-\Big(\dfrac34\Big)^{n} \end{gathered}\text{。}
其他种子总量始终为 34\dfrac34 夸脱。小米超过种子总量的一半时,满足 1−(34)n>341-\Big(\dfrac34\Big)^n\gt\dfrac34,即 (34)n<14\Big(\dfrac34\Big)^n\lt\dfrac14。
由于 (34)4=81256>14\Big(\dfrac34\Big)^4=\dfrac{81}{256}\gt\dfrac14,而 (34)5=2431024<14\Big(\dfrac34\Big)^5=\dfrac{243}{1024}\lt\dfrac14,所以第一次发生在第 55 天,即星期五。
所以正确答案是 D。
Each quart adds 14\dfrac14 quart of millet, and the birds leave 34\dfrac34 of the standing millet. On day nn the millet present is 14(1+34+⋯+(34)n−1)=1−(34)n. \begin{gathered} \dfrac14\left(1+\dfrac34+\cdots+\Big(\dfrac34\Big)^{n-1}\right) \\ = 1-\Big(\dfrac34\Big)^{n}. \end{gathered}
The other seeds always total 34\dfrac34 quart. Millet exceeds half when 1−(34)n>34,1-\Big(\dfrac34\Big)^n\gt\dfrac34, i.e. (34)n<14.\Big(\dfrac34\Big)^n\lt\dfrac14.
Since (34)4=81256>14\Big(\dfrac34\Big)^4=\dfrac{81}{256}\gt\dfrac14 but (34)5=2431024<14,\Big(\dfrac34\Big)^5=\dfrac{243}{1024}\lt\dfrac14, this first happens on day 5,5, which is Friday.
Thus, the correct answer is D.
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