2008 AMC 10A 第 14 题

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14.

老式电视屏幕的宽高比为 4:34:3。也就是说,宽与高之比为 4:34:3。许多电影的宽高比不是 4:34:3,所以有时会以“宽银幕黑边”方式在电视屏幕上播放,也就是把屏幕顶部和底部等高的条带变暗,如图所示。假设一部电影的宽高比为 2:12:1,并在一台对角线为 2727 英寸的老式电视上播放。每条变暗条带的高度是多少英寸?

Older television screens have an aspect ratio of 4:3.4:3. That is, the ratio of the width to the height is 4:3.4:3. The aspect ratio of many movies is not 4:3,4:3, so they are sometimes shown on a television screen by "letterboxing" — darkening strips of equal height at the top and bottom of the screen, as shown. Suppose a movie has an aspect ratio of 2:12:1 and is shown on an older television screen with a 2727-inch diagonal. What is the height, in inches, of each darkened strip?

22

2.252.25

2.52.5

2.72.7

33

答案:D
知识点:比与比例勾股定理矩形
难度评级:1410
解答:

因为屏幕为 4:34:3,对角线为 2727 英寸,所以 h:w:27=3:4:5h : w : 27 = 3 : 4 : 5,得到高 h=3527=16.2h = \dfrac{3}{5}\cdot 27 = 16.2,宽 w=4527=21.6w = \dfrac{4}{5}\cdot 27 = 21.6

点亮的 2:12:1 区域使用完整宽度 21.621.6,高度为 21.62=10.8\dfrac{21.6}{2} = 10.8

两条黑边平分剩余高度,所以每条高度为 16.210.82=2.7\dfrac{16.2 - 10.8}{2} = 2.7

所以正确答案是 D

Since the screen is 4:34:3 with a 2727-inch diagonal, h:w:27=3:4:5,h : w : 27 = 3 : 4 : 5, giving height h=3527=16.2h = \dfrac{3}{5}\cdot 27 = 16.2 and width w=4527=21.6.w = \dfrac{4}{5}\cdot 27 = 21.6.

The lit 2:12:1 region has the full width 21.621.6 and height 21.62=10.8.\dfrac{21.6}{2} = 10.8.

The two strips share the remaining height, so each has height 16.210.82=2.7.\dfrac{16.2 - 10.8}{2} = 2.7.

Thus, the correct answer is D.

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