2004 AMC 10B 第 14 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

14.

一个袋子最初只含红色和蓝色弹珠,且蓝色比红色多。向袋中加入红色弹珠,直到蓝色弹珠只占袋中弹珠的 13\tfrac{1}{3}。然后加入黄色弹珠,直到蓝色弹珠只占袋中弹珠的 15\tfrac{1}{5}。最后,将袋中蓝色弹珠的数量加倍。现在袋中弹珠有几分之几是蓝色?

A bag initially contains red marbles and blue marbles only, with more blue than red. Red marbles are added to the bag until only 13\tfrac{1}{3} of the marbles in the bag are blue. Then yellow marbles are added to the bag until only 15\tfrac{1}{5} of the marbles in the bag are blue. Finally, the number of blue marbles in the bag is doubled. What fraction of the marbles now in the bag are blue?

15\dfrac{1}{5}

14\dfrac{1}{4}

13\dfrac{1}{3}

25\dfrac{2}{5}

12\dfrac{1}{2}

答案:C
知识点:分数比与比例
难度评级:1240
解答:

设蓝色弹珠数为 BB。加入红色弹珠后,总数为 3B3B;加入黄色弹珠后,总数为 5B5B,蓝色仍为 BB

将蓝色弹珠数量加倍后,有 2B2B 个蓝色弹珠,总数变为 6B6B,所以蓝色所占比例为 2B6B=13\dfrac{2B}{6B} = \dfrac{1}{3}

所以正确答案是 C

Let there be BB blue marbles. After adding red marbles the total is 3B;3B; after adding yellow marbles the total is 5B,5B, still with BB blue.

Doubling the blue marbles gives 2B2B blue out of 6B6B total, which is 2B6B=13.\dfrac{2B}{6B} = \dfrac{1}{3}.

Thus, the correct answer is C.

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