2004 AMC 10A Problem 21

Below is the professionally curated solution for Problem 21 of the 2004 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10A solutions, or check the answer key.

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Concepts:sectorcircle areaannuluslinear equation

Difficulty rating: 1880

21.

Two distinct lines pass through the center of three concentric circles of radii 3,3, 2,2, and 1.1. The area of the shaded region in the diagram is 813\dfrac{8}{13} of the area of the unshaded region. What is the radian measure of the acute angle formed by the two lines? (Note: π\pi radians is 180180 degrees.)

π8\dfrac{\pi}{8}

π7\dfrac{\pi}{7}

π6\dfrac{\pi}{6}

π5\dfrac{\pi}{5}

π4\dfrac{\pi}{4}

Solution:

Let θ\theta be the acute angle. The shaded region has three parts: two acute sectors of the unit disk with total area θ,\theta, two obtuse sectors of the ring between radii 11 and 22 with total area 3(πθ),3(\pi - \theta), and two acute sectors of the ring between radii 22 and 33 with total area 5θ.5\theta.

Adding these gives a shaded area of θ+3(πθ)+5θ=3π+3θ. \theta + 3(\pi - \theta) + 5\theta = 3\pi + 3\theta.

The shaded region is 813\dfrac{8}{13} of the unshaded region, so it is 821\dfrac{8}{21} of the total area 9π.9\pi. Then 3π+3θ=821(9π)=24π7, 3\pi + 3\theta = \dfrac{8}{21}(9\pi) = \dfrac{24\pi}{7}, which gives θ=π7.\theta = \dfrac{\pi}{7}.

Thus, the correct answer is B.

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