2023 AMC 10A 第 2 题

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2.

一个大披萨的 13\frac{1}{3} 加上 3123\frac{1}{2} 杯橙子片的重量,等于同一个大披萨的 34\frac{3}{4} 加上 12\frac{1}{2} 杯橙子片的重量。一杯橙子片重 14\frac{1}{4} 磅。一个大披萨重多少磅?

The weight of 13\frac{1}{3} of a large pizza together with 3123\frac{1}{2} cups of orange slices is the same as the weight of 34\frac{3}{4} of a large pizza together with 12\frac{1}{2} cup of orange slices. A cup of orange slices weighs 14\frac{1}{4} of a pound. What is the weight, in pounds, of a large pizza?

1451\frac{4}{5}

22

2252\frac{2}{5}

33

3353\frac{3}{5}

答案:A
知识点:一次方程分数
难度评级:1080
解答:

设披萨重量为 pp。一杯橙子片重 14\frac14 磅,所以天平两边满足 13p+7214=34p+1214\frac13 p + \frac72 \cdot \frac14 = \frac34 p + \frac12 \cdot \frac14,也就是 13p+78=34p+18\frac13 p + \frac78 = \frac34 p + \frac18。整理披萨项得到 68=(3413)p=512p\frac68 = \left(\frac34 - \frac13\right)p = \frac{5}{12}p。因此 p=34125=95=145p = \frac34 \cdot \frac{12}{5} = \frac95 = 1\frac45。所以答案是 A

Let pp be the pizza's weight. A cup of orange slices is 14\frac14 pound, so the two sides balance as 13p+7214=34p+1214,\frac13 p + \frac72 \cdot \frac14 = \frac34 p + \frac12 \cdot \frac14, that is 13p+78=34p+18.\frac13 p + \frac78 = \frac34 p + \frac18. Collect the pizza terms: 68=(3413)p=512p.\frac68 = \left(\frac34 - \frac13\right)p = \frac{5}{12}p. So p=34125=95=145.p = \frac34 \cdot \frac{12}{5} = \frac95 = 1\frac45. Therefore, the answer is A.

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