2021 AMC 10A Fall 第 4 题

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4.

Lopez 先生上班有两条路线可选。路线 A 长 66 英里,他在这条路线上的平均速度为每小时 3030 英里。路线 B 长 55 英里,他在这条路线上的平均速度为每小时 4040 英里,但其中有一段 12\dfrac{1}{2} 英里的学校区域,平均速度为每小时 2020 英里。路线 B 比路线 A 快多少分钟?

Mr. Lopez has a choice of two routes to get to work. Route A is 66 miles long, and his average speed along this route is 3030 miles per hour. Route B is 55 miles long, and his average speed along this route is 4040 miles per hour, except for a 12\dfrac{1}{2}-mile stretch in a school zone where his average speed is 2020 miles per hour. By how many minutes is Route B quicker than Route A?

2342 \dfrac{3}{4}

3343 \dfrac{3}{4}

4124 \dfrac{1}{2}

5125 \dfrac{1}{2}

6346 \dfrac{3}{4}

答案:B
知识点:路程、速度与时间单位换算
难度评级:900
解答:

路线 A 所需时间为 分钟。 63060=12 \dfrac{6}{30} \cdot 60 = 12

路线 B 所需时间为 分钟。 (5.540+.520)60=8.25 \left(\dfrac{5 - .5}{40} + \dfrac{.5}{20}\right) \cdot 60 = 8.25

因此路线 B 快 128.25=3.7512 - 8.25 = 3.75 分钟。

所以正确答案是 B

Mr. Lopez would take 63060=12 \dfrac{6}{30} \cdot 60 = 12 minutes to travel on Route A.

On Route B, he would take (5.540+.520)60=8.25 \left(\dfrac{5 - .5}{40} + \dfrac{.5}{20}\right) \cdot 60 = 8.25 minutes.

The difference in times along these routes is 128.25=3.7512 - 8.25 = 3.75 minutes.

Thus, B is the correct answer.

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