2021 AMC 10B Spring 第 8 题

先试着解答 2021 AMC 10B Spring 第 8 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2021 AMC 10B Spring 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

Zhou 先生把从 11225225 的所有整数放入一个 15151515 列的方格中。他把 11 放在正中间的方格(第八行第八列),然后如图所示按顺时针方向逐个放入其他数。在从上往下数第二行中出现的最大数与最小数之和是多少?

Mr. Zhou places all the integers from 11 to 225225 into a 1515 by 1515 grid. He places 11 in the middle square (eighth row and eighth column) and places other numbers one by one clockwise, as shown in part in the diagram below. What is the sum of the greatest number and the least number that appear in the second row from the top?

367367

368368

369369

379379

380380

答案:A
知识点:找规律完全平方数
难度评级:1420
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文字解答:

在外层 15×1515\times15 的一圈中,最上面一行包含 211,212,,225211,212,\ldots,225,因此第二行中正好在 211211 下方的数是 210210

这是第二行的最大数。内层 13×1313\times13 螺旋的右上角是 132=16913^2=169。在整个方格第二行中,内层这一行的数从 157157169169,因此最小数是 157157

所求和为 210+157=367210+157=367。​

所以答案是 A

In the outer 15×1515\times15 ring, the top row contains 211,212,,225,211,212,\ldots,225, so the number just below 211211 in the second row is 210.210. This is the greatest number in the second row.

The inner 13×1313\times13 spiral has 132=16913^2=169 in its upper-right corner. In the second row of the full grid, the inner-ring entries run from 157157 to 169.169. Thus the least entry in that row is 157.157.

The required sum is 210+157=367.210+157=367.

Thus, the answer is A .

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