2017 AMC 10A 第 8 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

在一个 3030 人的聚会上,有 2020 个人彼此都认识,另有 1010 个人谁也不认识。认识的人拥抱,不认识的人握手。这个群体中会发生多少次握手?

At a gathering of 3030 people, there are 2020 people who all know each other and 1010 people who know no one. People who know each other hug, and people who do not know each other shake hands. How many handshakes occur?

240240

245245

290290

480480

490490

答案:B
知识点:数对计数组合
难度评级:1020
解答:

1010 个谁也不认识的人,每人都与 2020 个彼此认识的人握手,共 1020=20010 \cdot 20 = 200 次。

1010 个人彼此之间也都不认识,所以他们之间还有 (102)=45\binom{10}{2} = 45 次握手。

总数为 200+45=245200 + 45 = 245

所以正确答案是 B

Each of the 1010 people shake hands with each of the 2020 people. This results in 1020=20010 \cdot 20 = 200 handshakes.

There are also (102)=45\binom{10}{2} = 45 handshakes within the 1010 people (every pair of people shake hands).

Therefore, the total number of handshakes is 200+45=245.200 + 45 = 245.

Thus, B is the correct answer.

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