2015 AMC 10A 第 7 题

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7.

等差数列 131316161919\dotsc70707373 中有多少项?

How many terms are in the arithmetic sequence 13,13, 16,16, 19,19, ,\dotsc, 70,70, 73?73?

2020

2121

2424

6060

6161

答案:B
知识点:等差数列
难度评级:870
解答:

回忆等差数列的第 nn 项为 a+d(n1)a + d(n - 1),其中 aa 是首项,dd 是公差。

这里 a=13a = 13d=3d = 3。代入可得 所以正确答案是 B73=13+3(n1)20=n1n=21.\begin{aligned} 73 &= 13 + 3(n - 1) \\ 20&= n - 1 \\ n &= 21. \end{aligned}

Recall that the nnth term of an arithmetic sequence is a+d(n1),a + d(n - 1), where aa is the first term and dd is the common difference.

For us, a=13a = 13 and d=3.d = 3. Plugging these in, we get that 73=13+3(n1)20=n1n=21.\begin{aligned} 73 &= 13 + 3(n - 1) \\ 20&= n - 1 \\ n &= 21. \end{aligned} Thus, B is the correct answer.

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