2008 AMC 10B 第 2 题

先试着解答 2008 AMC 10B 第 2 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2008 AMC 10B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

如图所示,一个 4×44 \times 4 的日历日期方块。先将第二行数字的顺序反过来。然后将第四行数字的顺序反过来。最后,把两条对角线上的数字分别相加。两个对角线和的正差是多少?
A 4×44 \times 4 block of calendar dates is shown. The order of the numbers in the second row is to be reversed. Then the order of the numbers in the fourth row is to be reversed. Finally, the numbers on each diagonal are to be added. What will be the positive difference between the two diagonal sums?
22
44
66
88
1010
答案:B
知识点:日期与时间过程模拟
小提示:
将第 22 行和第 44 行反向后,写出新的方格。
After reversing rows 22 and 4,4, write out the new grid
大提示:
主对角线为 1,10,17,221,10,17,22,另一条对角线为 4,9,16,254,9,16,25。
The main diagonal reads 1,10,17,221,10,17,22 and the other reads 4,9,16,254,9,16,25
解答:
将第二行反为 11,10,9,811,10,9,8,第四行反为 25,24,23,2225,24,23,22 后,两条对角线分别为 1,10,17,221,10,17,22 和 4,9,16,254,9,16,25。
它们的和为 1+10+17+22=501+10+17+22=50 和 4+9+16+25=544+9+16+25=54,正差为 54−50=454-50=4。
所以正确答案是 B。
After reversing the second row to 11,10,9,811,10,9,8 and the fourth row to 25,24,23,22,25,24,23,22, the two diagonals are 1,10,17,221,10,17,22 and 4,9,16,25.4,9,16,25.
Their sums are 1+10+17+22=501+10+17+22=50 and 4+9+16+25=54,4+9+16+25=54, so the positive difference is 54−50=4.54-50=4.
Thus, the correct answer is B.
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