2006 AMC 10A 第 2 题

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2.

定义 xy=x3yx \otimes y = x^3 - y。求 h(hh)h \otimes (h \otimes h)

Define xy=x3y.x \otimes y = x^3 - y. What is h(hh)?h \otimes (h \otimes h)?

h-h

00

hh

2h2h

h3h^3

答案:C
知识点:自定义运算代数变形
难度评级:960
解答:

内层运算给出 hh=h3hh \otimes h = h^3 - h。因此 h(h3h)=h3(h3h)=h. \begin{aligned} h \otimes (h^3 - h) &= h^3 - (h^3 - h) \\ &= h. \end{aligned}

所以正确答案是 C

The inner operation gives hh=h3h.h \otimes h = h^3 - h. Then h(h3h)=h3(h3h)=h. \begin{aligned} h \otimes (h^3 - h) &= h^3 - (h^3 - h) \\ &= h. \end{aligned}

Thus, the correct answer is C.

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