2005 AMC 10B 第 7 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

一个圆内切于一个正方形,接着一个正方形内接于这个圆,最后一个圆内切于这个正方形。较小圆的面积与较大正方形的面积之比是多少?

A circle is inscribed in a square, then a square is inscribed in this circle, and finally, a circle is inscribed in this square. What is the ratio of the area of the smaller circle to the area of the larger square?

π16\dfrac{\pi}{16}

π8\dfrac{\pi}{8}

3π16\dfrac{3\pi}{16}

π4\dfrac{\pi}{4}

π2\dfrac{\pi}{2}

答案:B
知识点:圆面积正方形(几何)面积比
难度评级:1240
解答:

设较小圆半径为 rr,则它的面积为 πr2\pi r^2

外切于这个小圆的较小正方形边长为 2r2r,其对角线 22r2\sqrt2\,r 是较大圆的直径。所以较大圆半径为 2r\sqrt2\,r

外切于较大圆的较大正方形边长为 22r2\sqrt2\,r,面积为 8r28r^2

所求比为 πr28r2=π8. \dfrac{\pi r^2}{8r^2} = \dfrac{\pi}{8}.

所以正确答案是 B

Let the smaller circle have radius r,r, so its area is πr2.\pi r^2.

The smaller square, which circumscribes this circle, has side 2r,2r, and its diagonal 22r2\sqrt2\,r is the diameter of the larger circle. So the larger circle has radius 2r.\sqrt2\,r.

The larger square circumscribes the larger circle, so it has side 22r2\sqrt2\,r and area 8r2.8r^2.

The desired ratio is πr28r2=π8. \dfrac{\pi r^2}{8r^2} = \dfrac{\pi}{8}.

Thus, B is the correct answer.

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