2010 AMC 10A Problem 2 — Solution | LIVE by Po-Shen Loh

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2010 AMC 10A Problem 2

Attempt Problem 2 of the 2010 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

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2.

Four identical squares and one rectangle are placed together to form one large square as shown. The length of the rectangle is how many times as large as its width?

$\dfrac{5}{4}$

$\dfrac{4}{3}$

$\dfrac{3}{2}$

$2$

$3$

Answer: B

Concepts:ratio and proportion square (geometry)rectangle

Difficulty rating: 870

Solution:

WLOG, let the side lengths of the squares be $1.$

This means that the length of the rectangle is $4.$ We also have that the width must be $4 - 1 = 3.$

The desired ratio is then $\dfrac{4}{3}.$

Thus, B is the correct answer.

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