2010 AMC 10A Problem 3

Below is the professionally curated solution for Problem 3 of the 2010 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:linear equationratio and proportion

Difficulty rating: 960

3.

Tyrone had 9797 marbles and Eric had 1111 marbles. Tyrone then gave some of his marbles to Eric so that Tyrone ended with twice as many marbles as Eric. How many marbles did Tyrone give to Eric?

33

1313

1818

2525

2929

Solution:

Let xx be the number of marbles that Eric ends up with. Then Tyrone ends up with 2x.2x.

The total number of marbles is 97+11=108,97 + 11 = 108, so 3x=108 3x = 108 x=36.x = 36.

Then, Tyrone ends up with 362=7236 \cdot 2 = 72 marbles. This means he has to give away 9772=2597 - 72 = 25 marbles.

Thus, D is the correct answer.

Problem 3 in Other Years