2018 AMC 10B Problem 3

Below is the professionally curated solution for Problem 3 of the 2018 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10B solutions, or check the answer key.

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Concepts:basic countingsystematic listing

Difficulty rating: 950

3.

In the expression (x×x)+(x×x)(\underline{\phantom{x}} \times \underline{\phantom{x}}) + (\underline{\phantom{x}} \times \underline{\phantom{x}}) each blank is to be filled in with one of the digits 1,2,3,1, 2, 3, or 4,4, with each digit being used once. How many different values can be obtained?

22

33

44

66

2424

Solution:

Order inside a product doesn't matter, and neither does the order we add the two products. So all that matters is how the four digits split into two pairs. There are three splits: 12+34=14,1\cdot2 + 3\cdot4 = 14, 13+24=11,1\cdot3 + 2\cdot4 = 11, and 14+23=10.1\cdot4 + 2\cdot3 = 10. That's 33 different values. Thus, B is the correct answer.

Problem 3 in Other Years