2008 AMC 10A Problem 2

Below is the professionally curated solution for Problem 2 of the 2008 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 10A solutions, or check the answer key.

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Concepts:area ratio percentage

Difficulty rating: 840

A square is drawn inside a rectangle. The ratio of the width of the rectangle to a side of the square is $2:1.$ The ratio of the rectangle's length to its width is $2:1.$ What percent of the rectangle's area is inside the square?

$12.5$

$25$

$50$

$75$

$87.5$

Solution:

Let the side of the square be $s,$ so its area is $s^2.$

The width of the rectangle is $2s,$ and its length is $2 \cdot 2s = 4s,$ giving an area of $8s^2.$

The fraction inside the square is $\dfrac{s^2}{8s^2} = \dfrac{1}{8} = 12.5\%.$

Thus, the correct answer is A.

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