2024 AMC 10A Problem 2

Below is the professionally curated solution for Problem 2 of the 2024 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 10A solutions, or check the answer key.

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Concepts:system of equationslinear equation

Difficulty rating: 990

2.

A model used to estimate the time it will take to hike to the top of a mountain on a trail is of the form T=aL+bG,T = aL + bG, where aa and bb are constants, TT is the time in minutes, LL is the length of the trail in miles, and GG is the altitude gain in feet. The model estimates that it will take 6969 minutes to hike to the top if a trail is 1.51.5 miles long and ascends 800800 feet, as well as if a trail is 1.21.2 miles long and ascends 11001100 feet. How many minutes does the model estimate it will take to hike to the top if the trail is 4.24.2 miles long and ascends 40004000 feet?

240240

246246

252252

258258

264264

Solution:

Subtract the two equations 1.5a+800b=691.5a + 800b = 69 and 1.2a+1100b=691.2a + 1100b = 69 to kill the 69.69. That leaves 0.3a300b=0,0.3a - 300b = 0, so a=1000b.a = 1000b. Now substitute: 1500b+800b=2300b=69,1500b + 800b = 2300b = 69, so b=0.03b = 0.03 and a=30.a = 30. Then T=30(4.2)+0.03(4000)=126+120=246.T = 30(4.2) + 0.03(4000) = 126 + 120 = 246. Therefore, the answer is B.

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