2014 AMC 10A Problem 2

Below is the professionally curated solution for Problem 2 of the 2014 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10A solutions, or check the answer key.

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Concepts:ratefractiondate and time

Difficulty rating: 1140

2.

Roy's cat eats 13\dfrac{1}{3} of a can of cat food every morning and 14\dfrac{1}{4} of a can of cat food every evening. Before feeding his cat on Monday morning, Roy opened a box containing 66 cans of cat food. On what day of the week did the cat finish eating all the cat food in the box?

Tuesday

Wednesday

Thursday

Friday

Saturday

Solution:

The cat eats 13+14=712 \dfrac{1}{3} + \dfrac{1}{4} = \dfrac{7}{12} cans of food each day. This means that it will take the cat 6÷712=727 6 \div \dfrac{7}{12} = \dfrac{72}{7} days to finish all the foods. Note that this value is between 1010 and 11.11.

This means that the cat will finish eating the food in 1111 days, which is 1010 days after Monday.

1010 days after Monday is the same as 33 days after Monday, and as such, the answer is Thursday.

Thus, C is the correct answer.

Problem 2 in Other Years