2009 AIME II Problem 1

Attempt Problem 1 of the 2009 AIME II below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AIME II solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Before starting to paint, Bill had 130130 ounces of blue paint, 164164 ounces of red paint, and 188188 ounces of white paint. Bill painted four equally sized stripes on a wall, making a blue stripe, a red stripe, a white stripe, and a pink stripe. Pink is a mixture of red and white, not necessarily in equal amounts. When Bill finished, he had equal amounts of blue, red, and white paint left. Find the total number of ounces of paint Bill had left.
Answer: 114
Concepts:linear equationalgebraic manipulation
Small hint:
Equal leftovers mean the red used exceeds the blue used by 164−130,164 - 130, and similarly for white
Big hint:
Those excesses all went into the pink stripe, so one stripe’s worth of paint is 34+5834 + 58 ounces
Solution:
Say each stripe used ss ounces of paint. Blue was used only on the blue stripe, so ss ounces of blue were used. Since the three leftovers are equal and the colors started 3434 and 5858 ounces apart, red use exceeded blue use by 164−130=34164 - 130 = 34 ounces and white use exceeded blue use by 188−130=58188 - 130 = 58 ounces. That extra red and white is exactly the pink stripe, so s=34+58=92.s = 34 + 58 = 92.
Bill therefore had 130−92=38130 - 92 = 38 ounces of each color left, for a total of 3⋅38=1143 \cdot 38 = 114 ounces.
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