1995 AMC 8 第 16 题

先试着解答 1995 AMC 8 第 16 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1995 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

16.

三所中学的学生参加了一个暑期项目。艾伦中学的七名学生工作了 33 天。巴尔博亚中学的四名学生工作了 55 天。卡弗中学的五名学生工作了 99 天。学生工作的总报酬为 $774\$774。假设每名学生每天获得相同报酬,那么巴尔博亚中学的学生总共赚了多少?
Students from three middle schools worked on a summer project. Seven students from Allen School worked for 33 days. Four students from Balboa School worked for 55 days. Five students from Carver School worked for 99 days. The total amount paid for the students’ work was $774.\$774. Assuming each student received the same amount for a day’s work, how much did the students from Balboa School earn altogether?
$9.00\$9.00
$48.38\$48.38
$180.00\$180.00
$193.50\$193.50
$258.00\$258.00
答案:C
知识点:速率
小提示:
计算三所学校学生合计的工作量(以“人天”为单位)
Compute the total number of student-days worked across all three schools
大提示:
用 $774\$774 除以总人天数,得到每人每天的报酬
Divide $774\$774 by the total student-days to get the pay per student-day
解答:
总工作量为 7×3+4×5+5×97 \times 3 + 4 \times 5 + 5 \times 9 =21+20+45= 21 + 20 + 45 =86= 86 人天。
所以每人每天的报酬为 $774÷86=$9\$774 \div 86 = \$9。巴尔博亚学生的总工作量为 2020 人天,共赚得 20×$9=$18020 \times \$9 = \$180。
所以正确答案是 C。
The total student-days are 7×3+4×5+5×97 \times 3 + 4 \times 5 + 5 \times 9 =21+20+45= 21 + 20 + 45 =86.= 86.
So each student-day pays $774÷86=$9.\$774 \div 86 = \$9. Balboa worked 2020 student-days, earning 20×$9=$180.20 \times \$9 = \$180.
Thus, the correct answer is C .
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