2014 AMC 8 Problem 16

Below is the professionally curated solution for Problem 16 of the 2014 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 8 solutions, or check the answer key.

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Concepts:basic counting

Difficulty rating: 1170

16.

The "Middle School Eight" basketball conference has 88 teams. Every season, each team plays every other conference team twice (home and away), and each team also plays 44 games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams?

60 60

88 88

96 96

144 144

160 160

Solution:

Each team plays 44 non-conference games, for 84=328\cdot4=32 games involving Middle School Eight teams and non-conference opponents.

Within the conference, each of the 88 teams has 77 home games against the other teams, so there are 87=568\cdot7=56 conference games. The total is 32+56=8832+56=88.

Thus, B is the correct answer.

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