1986 AMC 8 第 24 题

先试着解答 1986 AMC 8 第 24 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1986 AMC 8 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

24.

King 初中的 600600 名学生午餐时被平均分成三组。每组在不同时间吃午餐。电脑随机把每名学生分到三组之一。三个朋友 Al、Bob 和 Carol 被分到同一午餐组的概率大约是

The 600600 students at King Middle School are divided into three groups of equal size for lunch. Each group has lunch at a different time. A computer randomly assigns each student to one of the three lunch groups. The probability that three friends, Al, Bob, and Carol, will be assigned to the same lunch group is approximately

127\dfrac{1}{27}

19\dfrac19

18\dfrac18

16\dfrac16

13\dfrac13

答案:B
知识点:基本概率独立事件
难度评级:1120
解答:

不论 Al 在哪一组,Bob 进入同一组的概率约为 199599\dfrac{199}{599},Carol 进入同一组的概率也约为 198598\dfrac{198}{598}

所以三人在同一组的概率约为 1995991985980.110\dfrac{199}{599} \cdot \dfrac{198}{598} \approx 0.11019\dfrac19

所以正确答案是 B

Whatever group Al is in, Bob joins that same group with probability 199599.\dfrac{199}{599}. If Bob does, Carol joins them with probability 198598.\dfrac{198}{598}.

Thus all three share a group with probability 1995991985980.110,\dfrac{199}{599} \cdot \dfrac{198}{598} \approx 0.110, closest to 19.\dfrac19.

Thus, the correct answer is B .

← 第 23 题#23
完整试卷

其他年份的第 24 题

1985 AMC 8 · 1987 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1993 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2004 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2009 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2017 AMC 8 · 2018 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8