2017 AMC 10B 第 7 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

Samia 骑自行车去拜访朋友,平均速度为每小时 1717 千米。当她走完到朋友家的路程的一半时,轮胎漏气了,于是她以每小时 55 千米的速度走完剩下的一半路程。

她总共花了 4444 分钟到达朋友家。四舍五入到最接近的十分之一千米,Samia 走了多远?

Samia set off on her bicycle to visit her friend, traveling at an average speed of 1717 kilometers per hour. When she had gone half the distance to her friend's house, a tire went flat, and she walked the rest of the way at 55 kilometers per hour.

In all, it took her 4444 minutes to reach her friend's house. In kilometers rounded to the nearest tenth, how far did Samia walk?

2.02.0

2.22.2

2.82.8

3.43.4

4.44.4

答案:C
知识点:路程、速度与时间一次方程
难度评级:1220
解答:

设她步行的距离为 dd。因为这等于她骑车的距离,记为 d=176=2.833d=\dfrac{17}{6}=2.833\ldots,所以 。 再设她步行的时间为 小时。因此骑车时间为 。 现在用速度的定义可得 这推出 所以 因而 因为 ,有 约为 2.82.8d17+d5=4460.\dfrac{d}{17}+\dfrac{d}{5}=\dfrac{44}{60}.

所以正确答案是 C

Let dd be the distance Samia walked. She bicycled the same distance, so her total travel time gives d17+d5=4460.\dfrac{d}{17}+\dfrac{d}{5}=\dfrac{44}{60}. Solving yields d=176=2.833,d=\dfrac{17}{6}=2.833\ldots, which rounds to 2.82.8 kilometers.

Thus, the correct answer is C .

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