2013 AMC 10A 第 9 题

先试着解答 2013 AMC 10A 第 9 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2013 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

在最近一场篮球比赛中,Shenille 只投三分球和两分球。她三分球命中率为 20%20\%,两分球命中率为 30%30\%。Shenille 共出手 3030 次。她得了多少分?
In a recent basketball game, Shenille attempted only three-point shots and two-point shots. She was successful on 20%20\% of her three-point shots and 30%30\% of her two-point shots. Shenille attempted 3030 shots. How many points did she score?
1212
1818
2424
3030
3636
答案:B
知识点:百分数一次方程
小提示:
设两分球和三分球出手数分别为 xx 和 yy。
Let xx and yy be the numbers of two-point and three-point attempts
大提示:
计算每种出手平均贡献多少分。
Compare the points earned per attempted shot type after applying the success percentages
解答:
设两分球出手 xx 次,三分球出手 yy 次。
那么 Shenille 命中 0.3x0.3x 个两分球和 0.2y0.2y 个三分球,总得分为 2⋅0.3x+3⋅0.2y=0.6x+0.6y。 2 \cdot 0.3x + 3 \cdot 0.2y = 0.6x + 0.6y\text{。}
我们知道 x+y=30 x + y = 30 0.6(x+y)=18。 0.6(x + y) = 18\text{。}
所以正确答案是 B。
Let xx be the number of two-point shots and yy be the number of three-point shots.
Then, Shenille makes 0.3x0.3x two-point shots and 0.2y0.2y three-point shots, for a total score of 2⋅0.3x+3⋅0.2y=0.6x+0.6y. 2 \cdot 0.3x + 3 \cdot 0.2y = 0.6x + 0.6y.
We know that x+y=30 x + y = 30 0.6(x+y)=18. 0.6(x + y) = 18.
Thus, B is the correct answer.
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