2010 AMC 10A 第 9 题

先试着解答 2010 AMC 10A 第 9 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2010 AMC 10A 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

回文数,例如 8343883438,是一个数字反过来读仍相同的数。数 xxx+32x + 32 分别是三位数和四位数回文数。xx 的各位数字之和是多少?

A palindrome, such as 83438,83438, is a number that remains the same when its digits are reversed. The numbers xx and x+32x + 32 are three-digit and four-digit palindromes, respectively. What is the sum of the digits of x?x?

2020

2121

2222

2323

2424

答案:E
知识点:回文数数字极限情形界定
难度评级:1280
解答:

因为 xx 至多为 999999,所以 x+32x + 32 至多为 10311031

同时 x+32x + 32 至少为 10001000

这个范围内唯一的回文数是 10011001,所以 x+32x + 32 必须等于它。

于是可求出该数: x+32=1001 x + 32 = 1001 x=969. x = 969.

各位数字之和为 9+6+9=24. 9 + 6 + 9 = 24.

所以正确答案是 E

Note that xx is at most 999.999. This means that x+32x + 32 has a maximum of 1031.1031.

Similarly, we have that the minimum value of x+32x + 32 is 1000.1000.

The only palindrome in this range is 1001,1001, so this is what x+32x + 32 equals.

Then x+32=1001 x + 32 = 1001 x=969. x = 969.

The sum of the digits is then 9+6+9=24. 9 + 6 + 9 = 24.

Thus, E is the correct answer.

← 第 8 题#8
完整试卷

其他年份的第 9 题