Question

一本要录成光盘的书，朗读需要 $412$ 分钟。每张光盘最多能容纳 $56$ 分钟的朗读。假设使用尽可能少的光盘，并且每张光盘包含相同长度的朗读内容。每张光盘包含多少分钟朗读？

A book that is to be recorded onto compact discs takes $412$ minutes to read aloud. Each disc can hold up to $56$ minutes of reading. Assume that the smallest possible number of discs is used and that each disc contains the same length of reading. How many minutes of reading will each disc contain?

$50.2$

$51.5$

$52.4$

$53.8$

$55.2$

答案：B

知识点：整除性估算

难度评级：1030

解答：

注意 $7 \cdot 56 = 392$ ，而 $8 \cdot 56 = 448$ ，所以最少需要 $8$ 张光盘。

每张光盘包含的朗读时间为 $412 \div 8 = 51.5.$

所以正确答案是 B。

Note that $7 \cdot 56 = 392$ and $8 \cdot 56 = 448,$ which means that the minimum number of discs needed is $8.$

Then the minutes of reading that each disc contains is $412 \div 8 = 51.5.$

Thus, B is the correct answer.

2010 AMC 10A 第 4 题

答案：B

难度评级：1030

解答：

其他年份的第 4 题