2006 AMC 10A 第 14 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

14.

若干个相连的圆环挂在一个钉子上,每个圆环厚 11 厘米。最上面的圆环外径为 2020 厘米。其余每个圆环的外径都比它上方的圆环少 11 厘米。最下面的圆环外径为 33 厘米。从最上面圆环的顶部到最下面圆环的底部的距离是多少厘米?

A number of linked rings, each 11 cm thick, are hanging on a peg. The top ring has an outside diameter of 2020 cm. The outside diameter of each of the other rings is 11 cm less than that of the ring above it. The bottom ring has an outside diameter of 33 cm. What is the distance, in cm, from the top of the top ring to the bottom of the bottom ring?

171171

173173

182182

188188

210210

答案:B
知识点:等差数列求和
难度评级:1330
解答:

最上面的圆环贡献完整外径 2020 厘米。因为圆环厚 11 厘米,每个圆环会比上方圆环的顶部低 22 厘米,所以每个较低圆环增加的是它的外径减去 22

外径依次为 20,19,,320, 19, \ldots, 3,所以下方各环增加的距离为 17,16,,117, 16, \ldots, 1。总距离为 20+(17+16++1)=20+17182=20+153=173. \begin{gathered} 20 + (17 + 16 + \cdots + 1) \\ = 20 + \frac{17 \cdot 18}{2} \\ = 20 + 153 \\ = 173. \end{gathered}

所以正确答案是 B

The top ring contributes its full outside diameter, 2020 cm. Because the rings are 11 cm thick, each ring hangs 22 cm below the top of the ring above it, so each lower ring adds its outside diameter minus 2.2.

The outside diameters run 20,19,,3,20, 19, \ldots, 3, so the added distances are 17,16,,1.17, 16, \ldots, 1. The total is 20+(17+16++1)=20+17182=20+153=173. \begin{gathered} 20 + (17 + 16 + \cdots + 1) \\ = 20 + \frac{17 \cdot 18}{2} \\ = 20 + 153 \\ = 173. \end{gathered}

Thus, the correct answer is B.

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