2021 AMC 12B Fall Problem 19

Attempt Problem 19 of the 2021 AMC 12B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

Regular polygons with 5,5, 6,6, 7,7, and 88 sides are inscribed in the same circle. No two of the polygons share a vertex, and no three of their sides intersect at a common point. At how many points inside the circle do two of their sides intersect?
5252
5656
6060
6464
6868
Answer: E
Concepts:regular polygoncounting intersections
Small hint:
Consider each pair of polygons separately
Big hint:
Two inscribed polygons with mm and nn sides in general position cross at 2min⁡(m,n)2\min(m, n) points
Solution:
For two convex polygons inscribed in the same circle with no shared vertices, each side of the smaller polygon crosses the larger polygon’s boundary exactly twice, so they meet at 2min⁡(m,n)2\min(m, n) points.
Summing over all pairs: (5,6),(5,7),(5,8)(5,6), (5,7), (5,8) give 1010 each; (6,7),(6,8)(6,7), (6,8) give 1212 each; (7,8)(7,8) gives 14.14.
The total is 3⋅10+2⋅12+14=68.3 \cdot 10 + 2 \cdot 12 + 14 = 68.
Thus, the correct answer is E.
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