1979 AMC 12 Problem 19

Attempt Problem 19 of the 1979 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1979 AMC 12 solutions, or check the answer key.

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19.

Find the sum of the squares of all real numbers satisfying the equation x25625632=0.x^{256}-256^{32}=0.

88

128128

512512

65,53665{,}536

2(25632)2(256^{32})

Answer: A
Concepts:exponentperfect powerzero product property
Difficulty rating: 1650
Small Hint:

Rewrite 25632256^{32} as a single power with exponent 256256

Big Hint:

Determine the two real values whose 256256th powers equal 22562^{256}

Solution:

Since 256=28,256=2^8, 25632=2256. 256^{32}=2^{256}. Thus (x2)256=1.(\frac{x}{2})^{256}=1. The real solutions are x=2x=2 and x=2,x=-2, and the sum of their squares is 4+4=8.4+4=8.

Therefore, the correct answer is A.

← Problem 18#18
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