2010 AMC 12B Problem 19

Below is the professionally curated solution for Problem 19 of the 2010 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 12B solutions, or check the answer key.

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Concepts:geometric sequencearithmetic sequencebounding to limit cases

Difficulty rating: 2180

19.

A high school basketball game between the Raiders and the Wildcats was tied at the end of the first quarter. The number of points scored by the Raiders in each of the four quarters formed an increasing geometric sequence, and the number of points scored by the Wildcats in each of the four quarters formed an increasing arithmetic sequence. At the end of the fourth quarter, the Raiders had won by one point. Neither team scored more than 100100 points. What was the total number of points scored by the two teams in the first half?

3030

3131

3232

3333

3434

Solution:

Let the Raiders score a,ar,ar2,ar3a, ar, ar^2, ar^3 (increasing geometric, r>1r\gt1) and the Wildcats a,a+d,a+2d,a+3da, a+d, a+2d, a+3d (increasing arithmetic), tied in the first quarter at a.a.

Every quarter score is a positive integer and each total is under 100,100, so the ratio and first term are small. Testing r=2r=2 gives Raiders 5,10,20,405, 10, 20, 40 with total 75.75.

The Wildcats then total 74=4a+6d=20+6d,74=4a+6d=20+6d, so d=9,d=9, giving 5,14,23,32.5, 14, 23, 32. The Raiders won 7575 to 74.74.

The first-half total is (5+10)+(5+14)=34.(5+10)+(5+14)=34.

Thus, the correct answer is E.

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