2024 AMC 10B Problem 9

Attempt Problem 9 of the 2024 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

Real numbers a,a, b,b, and cc have arithmetic mean 0.0. The arithmetic mean of a2,a^2, b2,b^2, and c2c^2 is 10.10. What is the arithmetic mean of ab,ab, ac,ac, and bc?bc?
−5-5
−103-\dfrac{10}{3}
−109-\dfrac{10}{9}
00
109\dfrac{10}{9}
Answer: A
Concepts:algebraic manipulationmean
Small hint:
Mean 00 means a+b+c=0;a + b + c = 0; mean 1010 means a2+b2+c2=30a^2 + b^2 + c^2 = 30
Big hint:
Use (a+b+c)2(a + b + c)^2 =a2+b2+c2= a^2 + b^2 + c^2 +2(ab+bc+ca)+ 2(ab + bc + ca)
Solution:
The means tell us a+b+c=0a + b + c = 0 and a2+b2+c2=30.a^2 + b^2 + c^2 = 30. Square the first: (a+b+c)2(a+b+c)^2 =a2+b2+c2= a^2 + b^2 + c^2 +2(ab+bc+ca),+ 2(ab + bc + ca), so 0=30+2(ab+bc+ca)0 = 30 + 2(ab + bc + ca) and ab+bc+ca=−15.ab + bc + ca = -15. Their mean is −153=−5.-\frac{15}{3} = -5. Thus, A is the correct answer.
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