2017 AMC 10A Problem 9

Below is the professionally curated solution for Problem 9 of the 2017 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10A solutions, or check the answer key.

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Concepts:distance rate and timeunit conversion

Difficulty rating: 1370

9.

Minnie rides on a flat road at 2020 kilometers per hour (kph), downhill at 3030 kph, and uphill at 55 kph. Penny rides on a flat road at 3030 kph, downhill at 4040 kph, and uphill at 1010 kph. Minnie goes from town AA to town B,B, a distance of 1010 km all uphill, then from town BB to town C,C, a distance of 1515 km all downhill, and then back to town A,A, a distance of 2020 km on the flat. Penny goes the other way around using the same route. How many more minutes does it take Minnie to complete the 4545-km ride than it takes Penny?

4545

6060

6565

9090

9595

Solution:

It will take Minnie 10÷5=210 \div 5 = 2 hours to travel the uphill distance. It will take her 15÷30=1215 \div 30 = \frac{1}{2} hours to travel the downhill distance.

Finally, it will take her 20÷20=120 \div 20 = 1 hour to travel the flat. This will take her a total of 60(2+12+1)=6072=210 \begin{align*}60\left(2 + \frac{1}{2} + 1\right) &= 60 \cdot \frac{7}{2} \\&= 210 \end{align*} minutes.

It will take Penny 20÷30=2320 \div 30 = \frac{2}{3} hours to travel the flat. It will take her another 15÷10=3215 \div 10 = \frac{3}{2} hours to travel the uphill.

Finally, it will take her 10÷40=1410 \div 40 = \frac{1}{4} hours to travel the downhill. This is a total of 60(23+32+14)=602912=145\begin{align*} 60\left(\dfrac{2}{3} + \dfrac{3}{2} + \dfrac{1}{4}\right) &= 60 \cdot \dfrac{29}{12} \\&= 145 \end{align*} minutes. The trip takes Minnie 210145=65210 - 145 = 65 more minutes to travel than Penny.

Thus, C is the correct answer.

Problem 9 in Other Years