2010 AMC 10B Problem 9

Below is the professionally curated solution for Problem 9 of the 2010 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:order of operationslinear equation

Difficulty rating: 1280

9.

Lucky Larry's teacher asked him to substitute numbers for a,a, b,b, c,c, d,d, and ee in the expression a(b(c(d+e)))a-(b-(c-(d+e))) and evaluate the result. Larry ignored the parentheses but added and subtracted correctly and obtained the correct result by coincidence. The number Larry substituted for a,a, b,b, c,c, and dd were 1,1, 2,2, 3,3, and 4,4, respectively. What number did Larry substitute for e?e?

5-5

3-3

00

33

55

Solution:

Ignoring the parentheses, Larry would get 1234+e=e8. 1 - 2 - 3 - 4 + e = e - 8.

Evaluating with the parentheses, one would get 1(2(3(4+e)))=1(2(1e))=1(3+e)=2e.\begin{align*} &1 - (2 -(3 - (4 + e)))\\ & = 1 - (2 - (-1 - e))\\ &= 1 - (3 + e) \\ &=-2 - e.\end{align*}

Both of these values are the same, so e8=2e e - 8 = -2 - e e=3. e = 3.

Thus, D is the correct answer.

Problem 9 in Other Years