2023 AMC 10A Problem 9

Below is the professionally curated solution for Problem 9 of the 2023 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10A solutions, or check the answer key.

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Concepts:digitsparitycasework

Difficulty rating: 1410

9.

A digital display shows the current date as an 88-digit integer, consisting of a 44-digit year, followed by a 22-digit month, followed by a 22-digit date within the month. For how many dates in 20232023 will each digit appear an even number of times in the digital display for that date?

55

66

77

88

99

Solution:

The year 20232023 already gives two 22s (even), one 0,0, and one 3.3. So to make every digit even overall, the four digits of MMMM and DDDD have to supply one more 0,0, one more 3,3, and then two digits equal to each other, all while keeping the count of 22s even. Run through the legal months and days of 20232023 under that rule and exactly 99 dates survive. Thus, E is the correct answer.

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