2018 AMC 10B Problem 9

Below is the professionally curated solution for Problem 9 of the 2018 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10B solutions, or check the answer key.

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Concepts:dice (probability)bijectionsymmetry

Difficulty rating: 1370

9.

The faces of each of 77 standard dice are labeled with the integers from 11 to 6.6. Let pp be the probability that when all 77 dice are rolled, the sum of the numbers on the top faces is 10.10. What other sum occurs with the same probability p?p?

1313

2626

3232

3939

4242

Solution:

Replace each die's value kk by 7k.7 - k. This pairs up outcomes one-to-one and keeps their probabilities, and it sends a total of ss to 77s=49s.7 \cdot 7 - s = 49 - s. So the sums ss and 49s49 - s are equally likely. The partner of 1010 is 4910=39.49 - 10 = 39. Thus, D is the correct answer.

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