2010 AMC 10B Problem 10

Below is the professionally curated solution for Problem 10 of the 2010 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10B solutions, or check the answer key.

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Concepts:distance rate and timelinear equation

Difficulty rating: 1370

10.

Shelby drives her scooter at a speed of 3030 miles per hour if it is not raining, and 2020 miles per hour if it is raining. Today she drove in the sun in the morning and in the rain in the evening, for a total of 1616 miles in 4040 minutes. How many minutes did she drive in the rain?

1818

2121

2424

2727

3030

Solution:

Note that 4040 minutes is 23\frac{2}{3} hours. Let Shelby drive hh hours in the sun.

Then she drives 23h\frac{2}{3} - h hours in the rain, which means she travels a total of 30h+20(23h)=10h+403 30h + 20\left(\dfrac{2}{3} - h\right) = 10h + \dfrac{40}{3} miles. We have this equals 16,16, so 10h+403=16 10h + \dfrac{40}{3} = 16 h=415. h = \dfrac{4}{15}.

Then Shelby drives 60(23415)=6025=24 60\left(\dfrac{2}{3} - \dfrac{4}{15}\right) = 60 \cdot \dfrac{2}{5} = 24 minutes in the rain.

Thus, C is the correct answer.

Problem 10 in Other Years