2023 AMC 10A Problem 2

Attempt Problem 2 of the 2023 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

The weight of 13\frac{1}{3} of a large pizza together with 3123\frac{1}{2} cups of orange slices is the same as the weight of 34\frac{3}{4} of a large pizza together with 12\frac{1}{2} cup of orange slices. A cup of orange slices weighs 14\frac{1}{4} of a pound. What is the weight, in pounds, of a large pizza?
1451\frac{4}{5}
22
2252\frac{2}{5}
33
3353\frac{3}{5}
Answer: A
Concepts:linear equationfraction
Small hint:
Let pp be the pizza’s weight and convert cups of orange slices to pounds using 14\frac14 pound per cup
Big hint:
Set 13p+72⋅14=34p+12⋅14\frac13 p + \frac72 \cdot \frac14 = \frac34 p + \frac12 \cdot \frac14 and solve for pp
Solution:
Let pp be the pizza’s weight. A cup of orange slices is 14\frac14 pound, so the two sides balance as 13p+72⋅14=34p+12⋅14,\frac13 p + \frac72 \cdot \frac14 = \frac34 p + \frac12 \cdot \frac14, that is 13p+78=34p+18.\frac13 p + \frac78 = \frac34 p + \frac18. Collect the pizza terms: 68=(34−13)p=512p.\frac68 = \left(\frac34 - \frac13\right)p = \frac{5}{12}p. So p=34⋅125=95=145.p = \frac34 \cdot \frac{12}{5} = \frac95 = 1\frac45. Therefore, the answer is A.
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