2018 AMC 10A Problem 2
Attempt Problem 2 of the 2018 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10A solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
2.
Liliane has more soda than Jacqueline, and Alice has more soda than Jacqueline. What is the relationship between the amounts of soda that Liliane and Alice have?
Liliane has more soda than Alice.
Liliane has more soda than Alice.
Liliane has more soda than Alice.
Liliane has more soda than Alice.
Liliane has more soda than Alice.
Answer: A
Small hint:
Use Jacqueline’s amount as the base variable
Big hint:
Compare Liliane’s amount directly to Alice’s amount
Solution:
Let be the number of gallons of soda that Jacqueline has. Then Alice has gallons, and Liliane has gallons.
Therefore, the relationship can be found by dividing the amount of soda that each has to yield which means Liliane has more soda than Alice.
Thus, A is the correct answer.
Problem 2 in other years
- 2000 AMC 10
- 2001 AMC 10
- 2002 AMC 10A
- 2002 AMC 10B
- 2003 AMC 10A
- 2003 AMC 10B
- 2004 AMC 10A
- 2004 AMC 10B
- 2005 AMC 10A
- 2005 AMC 10B
- 2006 AMC 10A
- 2006 AMC 10B
- 2007 AMC 10A
- 2007 AMC 10B
- 2008 AMC 10A
- 2008 AMC 10B
- 2009 AMC 10A
- 2009 AMC 10B
- 2010 AMC 10A
- 2010 AMC 10B
- 2011 AMC 10A
- 2011 AMC 10B
- 2012 AMC 10A
- 2012 AMC 10B
- 2013 AMC 10A
- 2013 AMC 10B
- 2014 AMC 10A
- 2014 AMC 10B
- 2015 AMC 10A
- 2015 AMC 10B
- 2016 AMC 10A
- 2016 AMC 10B
- 2017 AMC 10A
- 2017 AMC 10B
- 2018 AMC 10B
- 2019 AMC 10A
- 2019 AMC 10B
- 2020 AMC 10A
- 2020 AMC 10B
- 2021 AMC 10A Spring
- 2021 AMC 10B Spring
- 2021 AMC 10A Fall
- 2021 AMC 10B Fall
- 2022 AMC 10A
- 2022 AMC 10B
- 2023 AMC 10A
- 2023 AMC 10B
- 2024 AMC 10A
- 2024 AMC 10B
- 2025 AMC 10A
- 2025 AMC 10B